A teacher reaches into a bag that contains 6 plums, 14 clementine's, and 12nectarines. What is the probability that the teacher does not pick a nectarines? Youranswer can be a simplified fraction or rounded to the nearest whole percent.

Respuesta :

[tex]{\textcolor{red}{P(NOT\: nectarine)}}=\frac{5}{8}[/tex]

1) Given that the sum of all probabilities must be equal to 1, and there are 6 plums, 14 clementines, and 12 nectarines we can tell there are 14+12+6 objects:

14+12+6= 32 this is our subspace.

2) So let's find first the probability of that teacher picking a nectarine:

[tex]{\textcolor{orange}{P(nectarine)}}=\frac{12}{32}[/tex]

But notice, we don't want to know that we want the probability of not picking a nectarine so let's subtract that from 1 and write it this way:

3) We want to find the probability of the Complementary set to that:

[tex]\begin{gathered} {\textcolor{red}{P(NOT\: nectarine)}}=1-\frac{12}{32} \\ {\textcolor{red}{P(NOT\: nectarine)}}=\frac{32}{32}-\frac{12}{32} \\ {\textcolor{red}{P(NOTnectarine)}}=\frac{20}{32}=\frac{5}{8} \end{gathered}[/tex]

Note that we simplified this.