Given:
[tex]y=2x-1[/tex]
Find-:
Graph of equation
Explanation-:
The equation is:
[tex]y=2x-1[/tex]
The general form of a straight line is:
[tex]y=mx+c[/tex]
Where,
[tex]\begin{gathered} m\text{ = slope} \\ \\ c=\text{ y-intercept} \end{gathered}[/tex]
At x = 0 value of y is:
[tex]\begin{gathered} y=2x-1 \\ \\ y=2(0)-1 \\ \\ y=-1 \end{gathered}[/tex]
At y = 0 value of x is:
[tex]\begin{gathered} y=2x-1 \\ \\ 0=2x-1 \\ \\ x=\frac{1}{2} \end{gathered}[/tex]
So the line passes the point (0,-1) and (1/2, 0).
The graph of the line is:
