we must use trigonometric ratios, which applies for right triangles
on this case we will use
[tex]\tan (\alpha)=\frac{\text{opposite}}{\text{adjacent}}[/tex]
where alpha is the angle, opposite is the opposite side of the angle and adjacent the andjacent side of the angle different to hypotenuse
so replacing
[tex]\tan (44)=\frac{x}{2.8}[/tex]
and solving for x
[tex]\begin{gathered} x=2.8\tan (44) \\ x=2.7039\approx2.7 \end{gathered}[/tex]
the measure of x-side is 2.7 ft
