The length (L) and breadth (B) of the rectangle is given as,
[tex]\begin{gathered} L=5.4\times10^5 \\ B=275000 \end{gathered}[/tex]
The perimeter (P) of a rectangle is given by,
[tex]P=2(L+B)[/tex]
Substitute the values,
[tex]P=2\mleft\lbrace(5.4\times10^5)+275000\mright\rbrace[/tex]
Simplify the expression,
[tex]\begin{gathered} P=2\lbrace(5.4\times10^5)+(2.75\times10^5)\rbrace \\ P=2\lbrace(5.4+2.75)\times10^5\rbrace \\ P=2\lbrace(8.15)\times10^5\rbrace \\ P=16.3\times10^5 \\ P=1.63\times10^6 \end{gathered}[/tex]
Thus, the perimeter of the given triangle is obtained as,
[tex]1.63\times10^6\text{ meters}[/tex]
