1)
y = 3x + 19; y = 5x + 33
As we can see that, the LHS of the both the equations are y. So we can equate the RHS also,
[tex]\begin{gathered} y=3x+19=5x+33 \\ 3x+19=5x+33 \\ 3x-5x=33-19 \\ -2x=14 \\ x=-7 \end{gathered}[/tex]So, now to calculate y, let us take y = 3x+19 and put x = -7.
[tex]y=3\times(-7)+19=-21+19=12[/tex]So, the answer is, x = -7 and y = 12.