Answer:
P(A∩B)= P(A/B)P(B)
Explanation:
A relationship for a conditional probability of two events A and B is:
[tex]P(A\text{ /B)=}\frac{P(A\cap B)}{P(B)}[/tex]
Therefore, if we multiply both sides by P(B), we get:
[tex]\begin{gathered} P(\text{ A/B)P(B)=}\frac{P(A\cap B)}{P(B)}P(B) \\ P(\text{A/B)P(B)}=P(A\cap B) \end{gathered}[/tex]
So, the answer is:
P(A∩B)= P(A/B)P(B)
