11 years ago, Sallie invested $21,000.00 into a savings account. She now has$27,064.00. What simple interest rate was her savings account earning? Assume theinterest rate has not changed since the account was opened.

Given:
Principal amount= $21000
Total amount = $27064
Time t=11 years
The simple interest rate is calculated as,
[tex]\begin{gathered} A=P(1+rt) \\ \frac{A}{P}=1+rt \\ rt=\frac{A}{P}-1 \\ r=\frac{1}{t}(\frac{A}{P}-1) \end{gathered}[/tex]Here,
[tex]\begin{gathered} A=27064,P=21000,t=11 \\ r=\frac{1}{t}(\frac{A}{P}-1) \\ r=\frac{1}{11}(\frac{27064}{21000}-1) \\ r=\frac{1}{11}\times\frac{6064}{21000} \\ r=0.02625108 \end{gathered}[/tex]Simple interest rate is,
[tex]\begin{gathered} R=0.02625108\times100 \\ R=2.6251\text{ \%} \end{gathered}[/tex]Answer: 2.6251 %