Evaluate the value of definite integral.
[tex]\int ^4_2(2x^3-7)dx=\int ^4_22x^3dx-\int ^4_27dx[/tex][tex]\begin{gathered} \int ^4_22x^3dx-\int ^4_27dx=\lbrack\frac{2x^4}{4}\rbrack^4_2-\lbrack7x\rbrack^4_2 \\ =\frac{1}{2}\lbrack(4)^4-(2)^4\rbrack-7\lbrack4-2\rbrack \\ =\frac{1}{2}\lbrack256-16\rbrack-7\cdot2 \\ =\frac{1}{2}\cdot240-14 \\ =120-14 \\ =106 \end{gathered}[/tex]
Answer: 106
Option a is correct.
