Respuesta :

Given that the diameter of the wheel is d = 35 m.

Also, given that it completes 1 rev in 2 min 20 sec.

We have to find angular velocity, tangential velocity and centripetal acceleration.

The radius of the wheel will be

[tex]\begin{gathered} r\text{ =}\frac{d}{2} \\ =\frac{35}{2} \\ =17.5\text{ m} \end{gathered}[/tex]

The tangential velocity is

[tex]\begin{gathered} v=\frac{2\pi r}{t} \\ =\frac{2\times3.14\times17.5}{2\times60+20} \\ =0.785\text{ m/s} \end{gathered}[/tex]

The angular velocity will be

[tex]\begin{gathered} \omega=\frac{v}{r} \\ =\frac{0.785}{17.5} \\ =0.044\text{ rad/s} \end{gathered}[/tex]

The centripetal acceleration is

[tex]\begin{gathered} a_c=\frac{v^2}{r} \\ =\frac{(0.785)^2}{17.5} \\ =0.035m/s^2 \end{gathered}[/tex]