Given:
The current passing through the wire, I=3.45 A
To find:
The number of electrons passing per second.
Explanation:
The electric current is defined as the time rate of flow of charge through a point.
That is electric current is the total charge flowing through a point per second.
Thus the current through the given cross-section is
[tex]\begin{gathered} I=\frac{Q}{t} \\ \implies3.45\text{ A}=\frac{Q}{1\text{ s}} \\ \implies Q=3.45\text{ C} \end{gathered}[/tex]Where Q is the total charge passing through the cross-secion per esecond.
The charge of one electron is e=1.602×10⁻¹⁹ C
Thus he ctotal number of electrons passing through the cross-section per second is given by,
[tex]n=\frac{Q}{e}[/tex]On substituting the known values,
[tex]\begin{gathered} n=\frac{3.45}{1.602\times10^{-19}} \\ =2.16\times10^{19}\text{ } \end{gathered}[/tex]Final answer:
Thus the number of electrons passing through the cross-section per second is 2.15E+19 electrons/s
