if the jet comes to rest at 14.0 s what is the magnitude of its average acceleration? whats the direction?

Use the following formula for the average acceleration:
[tex]a_{\text{avg}}=\frac{v_2-v_1}{t_2-t_1}[/tex]where:
v2: final speed = 0m/s
v1: intial speed = 110 m/s
t2 - t1: time interval = 14.0 s
Replace the previous values into the expression for a_avg:
[tex]a_{\text{avg}}=\frac{0\frac{m}{s}-110\frac{m}{s}}{14.0s}=\frac{-110}{14.0}\frac{m}{s^2}=-\frac{7.85m}{s^2}[/tex]Hence, the magnitude of the average acceleration is approximately 7.85 m/s^2