A force exerted on a hydraulic cylinder with a diameter of 16.0 cm produces a pressure increase of 275 kPa. Calculate the force exerted on the cylinder.

Respuesta :

Answer:

5527.5 N

Explanation:

The pressure can be calculated as

[tex]P=\frac{F}{A}[/tex]

Where F is the force exerted and A is the area. Solving for F, we get:

[tex]F=PA[/tex]

Then, we can calculate the area as the area of the base of the cylinder. This area is equal to:

[tex]A=\pi r^2[/tex]

Where r is the radius. In this case, the diameter is 16.0 cm, so the radius is

r = diameter/2

r = 16.0 cm / 2

r = 8.0 cm

r = 0.08 m

Then, replacing the radius, we get:

[tex]\begin{gathered} A=(3.14)(0.08\text{ m\rparen}^2 \\ A=0.0201\text{ m}^2 \end{gathered}[/tex]

Therefore, replacing P = 275 kPa = 275000 Pa and A = 0.0201 m², we get that the force exerted is equal to

[tex]\begin{gathered} F=(275000Pa)(0.0201\text{ m}^2) \\ F=5527.5\text{ N} \end{gathered}[/tex]

So, the answer is 5527.5 N