Explanation:
To solve this question, we will make use of
Angle at the center is twice the angle at the circumference
[tex]arcBC=2\times\operatorname{\angle}BAC[/tex]
By substituting the values, we will have
[tex]\begin{gathered} arcBC=2\times\operatorname{\angle}BAC \\ arcBC=2\times29 \\ arcBC=58^0 \end{gathered}[/tex]
Hence,
The final answer is
[tex]Option\text{ }A[/tex]
