the length of a rectangle that is four times its width if the decks perimeter is 20 feet what is the decks area
we know that
the perimeter of rectangle is equal to
P=2(L+W)
we have
P=20 ft
L=4W
substitute the given values
20=2(4W+W)
solve for W
20=10W
W=2 ft
Find the value of L
L=4(2)=8 ft
Find out the area
The area is equal to
A=L*W
substitute
A=8*2+16 ft2
the answer is 16 square feet
