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A gardener has seven identical-looking tulip
bulbs, of which each will produce a different
color tulip. Four of the colors are unknown,
however one will become white, one will
become yellow, and one will become pink. He
plants them abitrarily in a row. When the
flowers start to bloom, what is the probability
that the yellow one is first in the row, the white
one is second, and the pink one is at the end of
the row?

A gardener has seven identicallooking tulipbulbs of which each will produce a differentcolor tulip Four of the colors are unknownhowever one will become white o class=

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Solution

Step-by-step explanation:

Given

There are 7 bulbs out of which 1 is Yellow and 1 is Pink and 1 is white

If a gardener randomly select 6 bulbs

Then the Probability of selecting yellow = 1/7

probability of selecting white = 1/7

and the probability of selecting pink = 1

[tex]\text{probability = }\frac{1}{7}\times\frac{1}{6}\times1=\frac{1}{42}=0.0238[/tex]

Therefore the correct answer is 0.0238

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