Given the following question:
[tex]\frac{1}{3}x-4=\frac{5}{3}x+8[/tex][tex]\begin{gathered} \frac{1}{3}x-4=\frac{5}{3}x+8 \\ -4+4=0 \\ 8+4=12 \\ \frac{1}{3}x=\frac{5}{3}x+8 \\ \frac{5}{3}-\frac{5}{3}=0 \\ \frac{1}{3}-\frac{5}{3}=-\frac{4}{3}x=12 \\ -\frac{4}{3}x=12 \\ 3(-\frac{4}{3})=-4x \\ 12\times3=36 \\ -4x=36 \\ -\frac{4x}{4}=x \\ 36\div-4=-9 \\ x=-9 \end{gathered}[/tex]
Your answer is x = -9
