The given system of equations is:
8a - 4b = 20...............(1)
5a - 8b = 62...............(2)
Multiply equation (1) by 2
16a - 8b = 40........................(3)
Subtract equation (2) from equation (3)
11a = -22
a = -22/11
a = -2
Substitute a = -2 into equation (1)
8a - 4b = 20
8(-2) - 4b = 20
-16 - 4b = 20
4b = -16-20
4b = -36
b = -36/4
b = -9
Therefore the solution to the system of equations is:
a = -2 and b = -9
