A satellite is in orbit 600 km above Earth's surface. Earth's radius is about 6370 km. Using the Pythagorean Theorem, the distance (x) from the satellite to Earth's horizon is ______ km.What is the km? round the answer to the nearest whole number.

Answer:
2829.13 km.
Explanation:
If the radius of the Earth is 6370 km, the distance of the segment CD is also 6370 km.
Then, the sides of the rigth triangle are:
CB = 6370 km
AC = AD + DC
AC = 600 km + 6370 km
AC = 6970 km
AB = x
So, using the Pythagorean theorem we can calculate the value of x as follows:
[tex]\begin{gathered} AB=\sqrt[]{(AC)^2-(CB)^2} \\ x=\sqrt[\square]{6970^2-6370^2} \end{gathered}[/tex]Because AC is the hypotenuse and CB is on the legs of the triangle.
Therefore, solving for x, we get:
[tex]x=2829.13\text{ km}[/tex]Then, the answer is:
The distance (x) from the satellite to Earth's horizon is 2829.13 km.