MarionD616208 MarionD616208

31-10-2022
Mathematics

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-TB +6r) = 14-1 .1+(3), GREMOR -R=17 3-18R=14.R 190 3-18 R&R=14-RAR Ral -3-172314 -3-178+3=1443 -4k + 2(5k - 6) = -3k - 39 n 1=-212

TB 6r 141 13 GREMOR R17 318R14R 190 318 RampR14RAR Ral 3172314 317831443 4k 25k 6 3k 39 n 1212 class=

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DeepH601121 DeepH601121

31-10-2022

We need to find k, so we have that

[tex]\begin{gathered} -4k+2(k-6)=-3k-39_{} \\ -4k+2k-12=-3k-39_{} \\ -4k+2k+3k=-39+12_{} \\ k=-27_{} \end{gathered}[/tex]

So the answer is k=-27.

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