For the given graph,A) find the slope (m) M=B) Fond the y-interceptor (b) b=C) write the equation of the line in slope-intercept form (I.e. y= mx + b ) Y=

For the given graphA find the slope m MB Fond the yinterceptor b bC write the equation of the line in slopeintercept form Ie y mx b Y class=

Respuesta :

Answer:

[tex]\begin{gathered} a_)\text{ -3} \\ b)\text{ -4} \\ c)\text{ -3x-4} \end{gathered}[/tex]

Explanation:

a) We want to get the slope of the line

To get this, we use two points on the line and apply the slope formula

We have the two points as:

[tex](0,-4)\text{ and \lparen-2,2\rparen}[/tex]

The slope of the line can be calculated using the formula:

[tex]m\text{ = }\frac{y_2-y_1}{x_2-x_1}\text{ = }\frac{2-(-4)}{-2-0}\text{ = }\frac{6}{-2}\text{ = -3}[/tex]

b) The y-intercept is the point at which the line crosses the y-axis

We have the point as (0,-4)

c) The equation of the line is thus:

[tex]\begin{gathered} y\text{ = mx + b} \\ m\text{ = -3 and b = -4} \\ y\text{ = -3x-4} \end{gathered}[/tex]