Solution
- Before we can find the value of
"The diagonals of a rhombus bisect the opposite angles into two equal angles"
- Thus, with this theorem, we can easily solve the problem as follows:
[tex]\begin{gathered} \angle\text{LMN}=65\degree \\ \text{Diagonal OM bisects }\angle\text{LMN according to the theorem.} \\ \\ \text{Thus, we have that:} \\ \angle\text{LMN}=\angle\text{LMV}+\angle\text{NMV} \\ \text{ Since OM bisects }\angle\text{LMN, we have that} \\ \angle\text{LMV}=\angle\text{NMV} \\ \\ \text{Thus, we can say that} \\ 2\angle\text{LMV}=\angle\text{LMN} \\ \\ \text{But }\angle\text{LMN}=65 \\ \\ 2\angle\text{LMV}=65 \\ \\ \text{Divide both sides by 2} \\ \\ \angle\text{LMV}=\frac{65}{2}=32.5\degree \end{gathered}[/tex]
Final Answer
The measure of
