Solution
- Convert 12∠-90 to rectangular form.
[tex]\begin{gathered} x=12\cos (-90)=0 \\ y=12\sin (-90)=-12 \\ \\ \text{The rectangular form of a complex number is} \\ z=x+jy \\ z=0+j(-12) \\ \\ \therefore z=-j12 \end{gathered}[/tex]Answer
The answer is
[tex]z=-j12[/tex]