The area of the drive is equal to the area of the front garden, which is a rectangle with a length of 5.2 m and a width of 4 m. The area of a rectangle is computed as follows:
[tex]A=w\cdot l[/tex]where w is the width and l is the length of the rectangle.
Substituting with w = 4 m and l = 5.2 m, we get:
[tex]\begin{gathered} A=4\cdot5.2 \\ A=20.8\text{ m}^2 \end{gathered}[/tex]The area of the drive is 20.8 square meters.
The back garden has a length of 8.3 m and a width of 6 m. Substituting with w = 6 m and l = 8.3 m into the area's formula, we get:
[tex]\begin{gathered} A=6\cdot8.3 \\ A=49.8\text{ m}^2\text{ } \end{gathered}[/tex]The area of the back garden is 49.8 square meters
The perimeter of a rectangle is computed as follow:
[tex]P=2\cdot(l+w)[/tex]Substituting with w = 6 m and l = 8.3 m, we get:
[tex]\begin{gathered} P=2\cdot(8.3+6) \\ P=2\cdot14.3 \\ P=28.6\text{ m} \end{gathered}[/tex]The perimeter of the back garden is 28.6 m