Assuming the pattern continues, what is the recursive formula for f (n) for the sequence 5 comma 3 comma nine fifths comma twenty seven twenty fifths and continues question mark

Assuming the pattern continues what is the recursive formula for f n for the sequence 5 comma 3 comma nine fifths comma twenty seven twenty fifths and continues class=

Respuesta :

Given:-

[tex]5,3,\frac{9}{5},\frac{27}{25},\ldots[/tex]

To find:-

Which function suits the sequence.

Considor the function,

[tex]f(n)=f(n-1)(\frac{3}{5}),f(1)=5[/tex]

When n = 2. we get,

[tex]\begin{gathered} f(2)=f(2-1)\times\frac{3}{5} \\ f(2)=f(1)\times\frac{3}{5} \\ f(2)=5\times\frac{3}{5} \\ f(2)=3 \end{gathered}[/tex]

So the second term is 3.

When n = 3. we get,

[tex]\begin{gathered} f(3)=f(3-1)\times\frac{3}{5} \\ f(3)=f(2)\times\frac{3}{5} \\ f(3)=3\times\frac{3}{5} \\ f(3)=\frac{9}{5} \end{gathered}[/tex]

So the third term is 9/5.

When n = 4. we get,

[tex]\begin{gathered} f(4)=f(4-1)\times\frac{3}{5} \\ f(4)=f(3)\times\frac{3}{5} \\ f(4)=\frac{9}{5}\times\frac{3}{5} \\ f(4)=\frac{27}{25} \end{gathered}[/tex]

So the fourth term is 27/25.

So this is the function which suits for the given sequence.