use the long division method to find the result when 4x3 + x2 272 + 18 is divided by 4x - 3. If there is a remainder, express the result in the form q(x) + r(x)/b(x)

use the long division method to find the result when 4x3 x2 272 18 is divided by 4x 3 If there is a remainder express the result in the form qx rxbx class=

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ANSWER:

[tex]x^{2}+x-6[/tex]

STEP-BY-STEP EXPLANATION:

We have the following polynomial:

[tex]4x^3+x^2-27x+18[/tex]

We must divide it by 4x - 3, using the long division method, therefore:

[tex]4x^3+x^2-27x+18\div \left(4x-3\right)[/tex]

We solve it below:

[tex]\begin{gathered} \text{ We divide the leading term of the dividend by the leading term of the divisor:} \\ \\ \frac{4x^3}{4x}=x^2 \\ \\ \text{ We multiply it by the divisor} \\ \\ x^2\cdot(4x-3)=4x^3-3x^2 \\ \\ \text{ We subtract the dividend from the obtained result: } \\ \\ 4x^3+x^2-27x+18-4x^3+3x^2=4x^2-27x+18 \\ \\ \text{ Finally it would be:} \\ \\ x^2+\frac{4x^2-27x+18}{4x-3} \end{gathered}[/tex]

Now, we repeat the same procedure:

[tex]\begin{gathered} \text{ We divide the leading term of the dividend by the leading term of the divisor:} \\ \\ \frac{4x^2}{4x}=x \\ \\ \text{ We multiply it by the divisor} \\ \\ x\cdot(4x-3)=4x^2-3x \\ \\ \text{ We subtract the dividend from the obtained result: } \\ \\ 4x^2-27x+18-4x^2-3x=-24x+18 \\ \\ \text{ Finally it would be:} \\ \\ x^2+x+\frac{-24+18}{4x-3} \end{gathered}[/tex]

We do the division for the last time and we would have the following:

[tex]\begin{gathered} \text{ We divide the leading term of the dividend by the leading term of the divisor:} \\ \\ \frac{-24x}{4x}=-6 \\ \\ \text{ We multiply it by the divisor} \\ \\ -6\cdot(4x-3)=-24x+18 \\ \\ \text{ We subtract the dividend from the obtained result: } \\ \\ -24x+18-24x+18=0 \\ \\ \text{ Finally it would be:} \\ \\ x^2+x-6 \end{gathered}[/tex]

So, the correct answer is:

[tex]4x^3+x^2-27x+18\div\left(4x-3\right)=x^2+x-6[/tex]