Respuesta :

[tex]\begin{gathered} 50<2x+10 \\ \text{Solving for x:} \\ \text{Subtract 10 from both sides:} \\ 50-10<2x+10-10 \\ 40<2x \\ \text{Divide both sides by 2:} \\ \frac{40}{2}<\frac{2x}{2} \\ 2020 \end{gathered}[/tex][tex]undefined[/tex]

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