[tex]p^4+3p^2[/tex]
Explanation
[tex]\begin{gathered} \frac{2p^5+6p^3}{2p} \\ \end{gathered}[/tex]
Step 1
factorize the numerator
[tex]\begin{gathered} \frac{2p^5+6p^3}{2p}=\frac{2p^5+2\cdot3p^3}{2p} \\ \frac{2p^5+6p^3}{2p}=\frac{2p^{4+1}+2\cdot3p^{2+1}}{2p} \\ \frac{2p^5+6p^3}{2p}=\frac{2pp^4+2p\cdot3p^2}{2p} \\ \frac{2p^5+6p^3}{2p}=\frac{2p(p^4+3p^2)}{2p} \end{gathered}[/tex]
Step 2
the 2p in the numerator cancels the 2p in the denominator,so
[tex]\begin{gathered} \frac{2p(p^4+3p^2)}{2p}=p^4+3p^2 \\ \\ p^4+3p^2 \end{gathered}[/tex]
I hope this helps you
