ANSWER
4/9
EXPLANATION
The probability of not drawing a B in each event is the same because the card is being replaced and the total number of cards is always the same. This probability is equivalent to 1 minus the probability of drawing a B,
[tex]P(notB)=1-P(B)[/tex]
There are 6 cards in total, and 2 of them are B. Thus, the probability of not drawing a B in each event is,
[tex]P(notB)=1-\frac{2}{6}=1-\frac{1}{3}=\frac{2}{3}[/tex]
The probability we want to find is the probability of not drawing a B twice in a row,
[tex]P(notB,notB)=P(notB)\cdot P(notB)=\frac{2}{3}\cdot\frac{2}{3}=\frac{4}{9}[/tex]
Hence, the probability of not drawing a B, then not drawing a B is 4/9.
