Score on last try: 0 of 7 pts. See Details for more.> Next questionGet a similar questionYou can retry this question belowWater Pressure ApplicationIn certain deep parts of oceans, the pressure of sea water, P, in pounds per square foot, at a depth5of d feet below the surface, is given by the following equation P = 15+ d. Use this equation to13complete the statements below. Round your answers to the nearest tenth as needed.PThe pressure of sea water is 100 pounds per square foot at a depth of 1surface of the water.Ifeet below the+The pressure of sea water is 67.5x pounds per square foot at a depth of 80 feet below thesurface of the water.Question Help: D Video D Post to forum

Score on last try 0 of 7 pts See Details for moregt Next questionGet a similar questionYou can retry this question belowWater Pressure ApplicationIn certain dee class=

Respuesta :

[tex]P=15+\frac{5}{13}d[/tex]

1. The pressure of sea water is 100 pounds per square foot (P=100) at a depth (d):

[tex]100=15+\frac{5}{13}d[/tex]

Solve d:

[tex]\begin{gathered} \text{Subtract 15 in both sides of the equation:} \\ 100-15=15-15+\frac{5}{13}d \\ \\ 85=\frac{5}{13}d \\ \\ \text{Multiply both sides of the equation by 13/5:} \\ \frac{13}{5}\cdot85=\frac{13}{5}\cdot\frac{5}{13}d \\ \\ 221=d \\ \\ d=221 \end{gathered}[/tex]

Then, The pressure of sea water is 100 pounds per square foot at a depth of 221 feet below the surface of the water

2. Find the pressure of the water (P) when d=80

[tex]\begin{gathered} P=15+\frac{5}{13}(80) \\ \\ P=15+\frac{400}{13} \\ \\ P=\frac{195+400}{13} \\ \\ P=\frac{595}{13} \\ \\ P=45.8 \end{gathered}[/tex]

Then, the pressure of sea water is 45.8 pounds per square foot at a depth of 80 feet below the surface of the water