The circle with its origin at 0, and a point (1, V3) means all points along the circle is the same distance from point zero (origin). From the information provided we can deduce a right angled triangle as shown below.
The points given as
[tex]P(1,\sqrt[]{3})[/tex]means that point P is 1 unit along the x-axis and square root 3 units along the y-axis. Note that the distance between point P and the origin is the radius. We can now solve for the radius by using the Pythagoras' theorem;
[tex]\begin{gathered} a^2=b^2+c^2 \\ \text{Where, a=hypotenuse, b and c=other two sides} \\ r^2=1^2+(\sqrt[]{3})^2 \\ r^2=1+(\sqrt[]{3}\times\sqrt[]{3}) \\ r^2=1+3 \\ r^2=4 \\ r=\sqrt[]{4} \\ r=2 \end{gathered}[/tex]The radius of the circle is 2 units
Option B is the correct answer
