Alejandro was picked by his teacher to find the integer that has the square root closest to 7without going over He wrote 52 on the boardWas he correct ? Explain your reasoning.

Solution
Yes, he is correct.
Here is the explanation
Since,
[tex]\begin{gathered} \sqrt{49}=7 \\ \sqrt{64}=8 \\ \\ \text{ since }49<57<64\Rightarrow\sqrt{49}<\sqrt{52}<\sqrt{64} \end{gathered}[/tex]Hence,
[tex]7<\sqrt{52}[/tex]