Respuesta :

The given expression is as given below

[tex]\frac{\lbrack15-(I-6+2I+\sqrt[]{9})\rbrack^2}{3-3^2}[/tex][tex]\frac{\lbrack15-(I-4I+\sqrt[]{9})\rbrack^2}{3-3^2}[/tex][tex]\begin{gathered} \frac{\lbrack15-(4+3)\rbrack^2}{3-3^2} \\ \frac{\lbrack15-(7)\rbrack^2}{3-3^2} \end{gathered}[/tex][tex]\begin{gathered} \frac{\lbrack15-7\rbrack^2}{3-3^2} \\ =\frac{8^2}{3-27} \\ =\frac{64}{-24} \\ =\frac{-8}{3} \end{gathered}[/tex][tex]=-2\frac{2}{3}[/tex]

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