Given:
A pocket full of change
The change contains 4 pennies, 2 nickels, and 3 dimes.
so, the number of coins = 4 + 2 + 3 = 9
The probability of choosing the first dime = 3/9
so, the number of coins will be = 9 - 1 = 8
The probability of choosing the second dime = 3/8
So, the probability if be randomly choosing 2 coins they are both dimes =
[tex]\frac{3}{9}\cdot\frac{3}{8}=\frac{1}{8}[/tex]Dependent
