9.
(13x + 9)⁰ and (15x - 1)⁰ are vertical angles, therefore:
[tex]13x+9=15x-1[/tex]
Solve for x:
[tex]\begin{gathered} 15x-13x=9+1 \\ 2x=10 \\ x=\frac{10}{2} \\ x=5 \end{gathered}[/tex]
(4y + 2)⁰ and 2(3y - 25)⁰ are also vertical angles, so:
[tex]\begin{gathered} 4y+2=2(3y-25) \\ 4y+2=6y-50 \end{gathered}[/tex]
Solve for y:
[tex]\begin{gathered} 6y-4y=50+2 \\ 2y=52 \\ y=\frac{52}{2} \\ y=26 \end{gathered}[/tex]
Therefore:
[tex]\begin{gathered} 13x+9=13(5)+9=74 \\ 15x-1=15(5)-1=74 \\ 4y+2=4(26)+2=106 \\ 2(3y-25)=2(3(26)-25)=2(53)=106 \end{gathered}[/tex]
