An object attached to a spring is being pulled across a flat frictionless surface. The spring constant is 48 N/m, the object is accelerating at 1.1 m/s2, and the mass of the object is 38 kg. What distance is the springstretched?

The magnitude of the restoring force acting on the object is,
[tex]F=kx[/tex]where k is the spring constant, and x is the distance of the spring stretched.
The magnitude of the force acting on the object in terms of the acceleration is,
[tex]F=ma[/tex]where m is the mass of the object and a is the acceleration.
From both the values of the force,
[tex]kx=ma[/tex]Substitutitng the known values,
[tex]\begin{gathered} 48\times x=38\times1.1 \\ x=0.871\text{ m} \end{gathered}[/tex]Thus, the value of the stretched distance of the string is 0.871 m.