ANSWER:
[tex]\begin{gathered} \text{ The point-slope form} \\ y-2=-\frac{6}{7}\cdot(x-1) \\ \text{ The slope-intercept form} \\ y=-\frac{6}{7}x+\frac{20}{7} \end{gathered}[/tex]STEP-BY-STEP EXPLANATION:
We have that the equation of the line in its point and slope form is the following:
[tex]y-y_1=m\cdot(x-x_1)[/tex]We replace and the equation would be like this:
[tex]y-2=-\frac{6}{7}\cdot(x-1)[/tex]We have that the equation of the line in its slope intercept form has the following form:
[tex]y=mx+b[/tex]So what we have is to solve for y, like this:
[tex]\begin{gathered} y=-\frac{6}{7}x+\frac{6}{7}+2 \\ y=-\frac{6}{7}x+\frac{6}{7}+\frac{14}{7} \\ y=-\frac{6}{7}x+\frac{20}{7} \end{gathered}[/tex]