Given the equation:
[tex]\text{ x}^2\text{ + 3x - 4 = 0}[/tex]To find x, since the equation is in the standard form of Quadratic Equation, we will be using the Quadratic formula:
[tex]\text{ x =}\frac{-b\text{ }\pm\text{ }\sqrt[]{b^2-4ac}}{2a}[/tex]At,
[tex]ax^2\text{ + bx + c = 0}[/tex]Where,
a = coefficient at x² = 1
b = coefficient at x = 3
c = constant = -4
Let's plug in the values to find for x:
[tex]\text{ x =}\frac{-b\text{ }\pm\text{ }\sqrt[]{b^2-4ac}}{2a}[/tex][tex]undefined[/tex]
