point O is the center of the regular nonagon shown below. find the angle of rotation about O that maps F to IA....° rotation about O maps F to I

the angle between each side or vertex of an nonagon is 40 °
we have the sum of 3 angles
FOG=40
FOH=40
HOI=40
so the rotaton about O maps F to I is
[tex]40+40+40=120[/tex]120°