The pH is calculated using the formula:
[tex]pH=-\log[H^+][/tex]The question gives the pH of lemon juice to be 2.2.
Hence, the formula is written to be:
[tex]2.2=-\log[H^+][/tex]Multiply both sides by -1:
[tex]\log[H^+]=-2.2[/tex]Since the log is in base 10, we have:
[tex]\log_{10}[H^+]=-2.2[/tex]Apply the law of log