Respuesta :

Let:

e = Number of economy seats sold

d = Number of deluxe seats sold

There are some restrictions on the tour:

* At least 1 economy seat must be sold, that is:

e ≥ 1

* At least 6 deluxe seats must be sold, thus:

d ≥ 6

* The maximum number of passengers is 30, thus:

e + d ≤ 30

The profit is $40 for each economy seat sold and $35 for each deluxe seat sold:

P = 40e + 35d

This is the function to maximize subject to the restrictions above. We'll use the graph method.

It requires graphing the lines e = 1, d = 6, and e + d = 30 on the same grid and find the feasible region.

The feasible region is a triangle with vertices at (1, 6), (24, 6), and (1, 29).

Now we test the vertices in the function to maximize.

For (1, 6):

P = 40(1) + 35(6)

P = 250.

For (24, 6):

P = 40(24) + 35(6)

P = 1170

For (1, 29):

P = 40(1) + 35(29)

P = 1055

Thus, the maximum profit ($1120) is done when 24 economy seats and 6 deluxe seats are sold.

Ver imagen ShayeY324587