Respuesta :
Answer: 59.41 grams of Na2S
Explanation
Na2S will be formed from the chemical reaction below :
[tex]2Na\text{ +S }\Rightarrow\text{ Na}_2S[/tex]We are given :
• Mass of Na = 35.0 g rams
,• Molar mass Na = 22,989769 g/mol
(1) Calculate moles Na
[tex]\begin{gathered} Moles\text{ Na =}\frac{Mass\text{ }}{Molecular\text{ mass }} \\ \text{ = }\frac{35\text{ g }}{22.989769g.mol^{-1}} \\ \text{ }\therefore\text{ Moles Na =1.522 moles of Sodium } \end{gathered}[/tex](2) From stoichiometry, the balanced equation informs us that :
2 mole Na will produce 1 mole Na2S
Then , 1.522 moles Na will produce X moles Na2S
Therefore, X moles Na2S = (1.522mole Na * 1 mole Na2S)/ 2 moles Na
=0.761 moles on Na2S will be produced .
(3) Calculate Mass of Na2S
• Molecular mass Na2S = 78,0452 g/mol
[tex]\begin{gathered} Mass\text{ Na}_2S\text{ = Molecular mass Na}_2S\text{ * moles Na}_2S \\ \text{ = 78.0452g/mol *0.761 moles } \\ \text{ =59.41 grams } \end{gathered}[/tex]