The equation of the line in two point form is given by:
[tex]\frac{y-y_1}{x-x_1}=\frac{y_2-y_1}{x_2-x_1}[/tex]Substitute the points to get:
[tex]\begin{gathered} \frac{y-2}{x-6}=\frac{-4-2}{8-6} \\ \frac{y-2}{x-6}=-3 \\ y-2=-3x+18 \\ 3x+y-20=0 \end{gathered}[/tex]Hence the equation of the line is 3x+y-20=0
