Problem statement: we have been given a task to find the area of the sector.
We are given some parameters:
[tex]\begin{gathered} \text{central angle=170}^0 \\ \text{radius}=17\operatorname{mm} \\ \end{gathered}[/tex]Method: We will apply the formula:
[tex]\begin{gathered} A=\frac{\theta}{360}\times\pi r^2 \\ \text{where} \\ \theta=\text{ central angle} \\ r=17\operatorname{mm} \\ A=\text{Area of the sector} \\ \pi=\frac{22}{7} \end{gathered}[/tex]Thus, applying the formula
[tex]A=\frac{170}{360}\times\frac{22}{7}\times17^2[/tex][tex]A=428.7\operatorname{mm}^2[/tex]The area of the sector is 428.7mm²
The answer is option 3
