the equation (x+2)(2x+3)=0 has two solutions. one is an integer, the other is a fraction

Given the following euqation:
[tex]\text{ (x + 3)(2x + 3)}[/tex]Let's determine the integer solution, we'll use (x + 3).
[tex]\text{ x + 2 = 0}[/tex][tex]\text{ x + 2 - 2 = 0 - 2}[/tex][tex]\text{ x = -2}[/tex]Therefore, the integer solution is -2.
Next, let's determine the fraction solution, we'll use (2x + 3).
[tex]\text{ 2x + 3 = 0}[/tex][tex]\text{ 2x + 3 - 3 = 0 - 3}[/tex][tex]\text{ 2x = - 3}[/tex][tex]\text{ }\frac{\text{2x}}{2}\text{ = }\frac{\text{-3}}{2}[/tex][tex]\text{ x = -}\frac{3}{2}[/tex]Therefore, the fraction solution is -3/2.
In Summary,
The integer solution is : -2
The fraction solution is : -3/2