In need of help w/ part 1-3 Question is in the image

Explanation: We are to find the quadrant where the terminal side of the following angle is found
In the cartesian plane when the two axes, X-axis and Y-axis, intersect with each other at 90º there are four regions formed around them, and those regions are called quadrants.
The way to go about the question will be to find the coterminal angles to your given angle, you need to add or subtract a multiple of 360°
so for part A
[tex]\begin{gathered} -452=\text{ -452+2\lparen360\rparen=-425+720=268}^0 \\ 268^0\text{ is in the third quadrant} \end{gathered}[/tex]So
-452 is in quadrant 3
Part B
631 degrees is equivalent to
[tex]\begin{gathered} 631-360=271^0 \\ \\ 271^0\text{ is in the fourth quadrant} \\ \end{gathered}[/tex]so 631 is in quadrant 4
Part C
361 is equivalent to
[tex]\begin{gathered} 361-360=1^0 \\ 1^0\text{ is in the first quadrant} \end{gathered}[/tex]361 is in quadrant 1
Part D
[tex]155\text{ is in quadrant two}[/tex]155 is in quadrant 2