Given the equation of a line:
[tex]y\text{ - 4 = }\frac{2}{3}\text{ (x - 3)}[/tex]
Step 1: Obtain the slope of the given line
Writing this equation in the standard slope-intercept form, we will obtain the following
[tex]\begin{gathered} y\text{ - 4 = }\frac{2}{3}x\text{ - }\frac{2}{3}\times3 \\ \\ y\text{ - 4 =}\frac{2}{3}x\text{ - 2} \end{gathered}[/tex]
[tex]y\text{ =}\frac{2}{3}x\text{ - 2+ 4}[/tex]
[tex]y\text{ = }\frac{2}{3}x\text{ + 2}[/tex]
If we compare this to y = mx + b, where m is the slope and b the intercept
the slope of the line is
[tex]\frac{2}{3}[/tex]
Step 2: Getting the equation of the line,
The equation of a line given a slope is given by
[tex]\text{slope = }\frac{y-y_1}{x-x_1}[/tex]
where x1 and y1 are the coordinates of the points parallel, in this case
x1 =1, y1 = -2
[tex]\frac{2}{3}\text{ =}\frac{y-\text{ (-2)}}{x\text{ -1}}[/tex]
[tex]\frac{2}{3}\text{ =}\frac{y\text{ +2}}{x\text{ - 1}}[/tex]
Cross multiplying
2 (x - 1) = 3 (y +2)
expand the parenthesis
2x - 2 = 3y + 6
3y = 2x -2 -6
3y = 2x - 8
Divide both sides by 3
[tex]y\text{ = }\frac{2}{3}x\text{ - }\frac{8}{3}[/tex]
Answer is y = 2x/3 - 8/3