Question 1
Given:
Base of triangle, b = 32 mm
Height of triangle, h = 35 mm
Let's find the area of the triangle.
To solve for the area, apply the formula:
[tex]\text{Area of triangle = }\frac{1}{2}\ast b\ast h[/tex]Thus, we have:
[tex]\begin{gathered} \text{Area = }\frac{1}{2}\ast32\ast35 \\ \\ \text{Area = 16}\ast35 \\ \\ \text{ Area = 560 mm}^2 \end{gathered}[/tex]Area: 560 mm²
• Question 2:
Given:
Area of parallelogram, A = 168 yd²
Height of parallelogram, h = 8 yd
Let's find the base, b, of the parallelogram.
To find the base, apply the area of a parallelogram formula:
[tex]\text{Area}=b\ast h[/tex]Input values into the formula:
[tex]168=b\ast8[/tex]Let's solve for b.
Divide both sides by 8:
[tex]\begin{gathered} \frac{168}{8}=\frac{b\ast8}{8} \\ \\ 21=b \\ \\ b=21 \end{gathered}[/tex]Therefore, the base of the parallelogram is 21 yards
ANSWER:
• 1. Area: ,560 mm,²
• 2. Base: ,21 yd
