The population mean annual salary for a environmental compliance specialist is about 60,500A random sample of 43 specialist is drawn from the population. What is the probability that the sample mean is less than 58,000

Respuesta :

To answer this question, we first have to find the sample z score, and the formula is:

[tex]z=\frac{(\frac{x-\mu}{\sigma})}{\sqrt[]{n}}[/tex]

Substituting the given values into the formula above:

[tex]\begin{gathered} z=\frac{\frac{58,000-60,500}{5800}}{\sqrt[]{43}} \\ z=-0.0657 \end{gathered}[/tex]

So by using the z-score calculator, the probability at a z-score less than -0.0657 is

[tex]0.4738[/tex]