The given question is
We will use the order of operations to solve the question
[tex]n^6\ast n^5[/tex]We will add their powers to make the multiplication
[tex]n^6\ast n^5=n^{6+5}=n^{11}[/tex]Now, we will divide n^11 by n^4, to do that we will subtract their powers
[tex]\frac{n^{11}}{n^4}=n^{11-4}=n^7[/tex]Then multiply n^7 by n^3 by adding their powers
[tex]n^7\ast n^3=n^{7+3}=n^{10}[/tex]Then divide it by n^2, to do that subtract their powers
[tex]\frac{n^{10}}{n^2}=n^{10-2}=n^8[/tex]At last, multiply the answer by n
[tex]n^8\ast n=n^{8+1}=n^9[/tex]The answer is n^9
