Given data
*The given speed of the compact car is v = 30 m/s
*The value of the acceleration due to gravity is g = 9.8 m/s^2
The expression for the height of the car is given by the conservation of energy as
[tex]\begin{gathered} U_p=U_k \\ mgh=\frac{1}{2}mv^2 \\ h=\frac{v^2}{2g} \end{gathered}[/tex]Substitute the known values in the above expression as
[tex]\begin{gathered} h=\frac{(30)^2}{2\times9.8} \\ =45.91\text{ m} \end{gathered}[/tex]Hence, the height of the car would have to be dropped them is h = 45.91 m
